Description
A projectile is fired from a catapult. The angle of elevation above the horizontal for the launch is alpha (in radians or degrees). For a given speed v0 the initial velocity is v(0) = <v0 cos(alpha), v0 sin(alpha)>. You should verify this. The initial launch position is (x0,y0).
We use g as the acceleration due to gravity (either 32 ft/sec2 or 9.81 m/sec2). The functions x(t) (down range)and y(t) (height) describe the coordinates of the projectile at time t in seconds. Let us not take into consideration air resistance. If we did how would the trajectories change?
The distance that a catapult fires a projectile depends on two factors: (1) the projectile's initial velocity v0 and (2) the angle of elevation, alpha, of the launch of the projectile from horizontal. Suppose you can give the projectile an initial velocity of v0 = 300 ft/sec.
Investigate the effects of varying the angle of elevation from the horizontal on the horizontal range of the projectile. What angle maximizes this range?
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